## 4.2 Working with Radiometric Integrals

A frequent task in rendering is the evaluation of integrals of radiometric quantities. In this section, we will present some tricks that can make it easier to do this. To illustrate the use of these techniques, we will take the computation of irradiance at a point as an example. Irradiance at a point with surface normal due to radiance over a set of directions  is

(4.7)

where is the incident radiance function (Figure 4.5) and the factor in the integrand is due to the factor in the definition of radiance. is measured as the angle between and the surface normal . Irradiance is usually computed over the hemisphere of directions about a given surface normal .

The integral in Equation (4.7) is with respect to solid angle on the hemisphere and the measure corresponds to surface area on the unit hemisphere. (Recall the definition of solid angle in Section 3.8.1.)

### 4.2.1 Integrals over Projected Solid Angle

The various cosine factors in the integrals for radiometric quantities can often distract from what is being expressed in the integral. This problem can be avoided using projected solid angle rather than solid angle to measure areas subtended by objects being integrated over. The projected solid angle subtended by an object is determined by projecting the object onto the unit sphere, as was done for the solid angle, but then projecting the resulting shape down onto the unit disk that is perpendicular to the surface normal (Figure 4.6). Integrals over hemispheres of directions with respect to cosine-weighted solid angle can be rewritten as integrals over projected solid angle.

The projected solid angle measure is related to the solid angle measure by

so the irradiance-from-radiance integral over the hemisphere can be written more simply as

For the rest of this book, we will write integrals over directions in terms of solid angle, rather than projected solid angle. In other sources, however, projected solid angle may be used, so it is always important to be aware of the integrand’s actual measure.

### 4.2.2 Integrals over Spherical Coordinates

It is often convenient to transform integrals over solid angle into integrals over spherical coordinates using Equation (3.7). In order to convert an integral over a solid angle to an integral over , we need to be able to express the relationship between the differential area of a set of directions and the differential area of a pair (Figure 4.7). The differential area on the unit sphere is the product of the differential lengths of its sides, and . Therefore,

(4.8)

(This result can also be derived using the multidimensional transformation approach from Section 2.4.1.)

We can thus see that the irradiance integral over the hemisphere, Equation (4.7) with , can equivalently be written as

If the radiance is the same from all directions, the equation simplifies to .

### 4.2.3 Integrals over Area

One last useful transformation is to turn integrals over directions into integrals over area. Consider the irradiance integral in Equation (4.7) again, and imagine there is a quadrilateral with constant outgoing radiance and that we could like to compute the resulting irradiance at a point . Computing this value as an integral over directions or spherical coordinates is in general not straightforward, since given a particular direction it is nontrivial to determine if the quadrilateral is visible in that direction or . It is much easier to compute the irradiance as an integral over the area of the quadrilateral.

Differential area on a surface is related to differential solid angle as viewed from a point  by

(4.9)

where is the angle between the surface normal of and the vector to , and is the distance from to (Figure 4.8). We will not derive this result here, but it can be understood intuitively: if is at distance 1 from  and is aligned exactly so that it is perpendicular to , then , , and Equation (4.9) holds. As moves farther away from , or as it rotates so that it is not aligned with the direction of , the and factors compensate accordingly to reduce .

Therefore, we can write the irradiance integral for the quadrilateral source as

where is the emitted radiance from the surface of the quadrilateral, is the angle between the surface normal at and the direction from to the point on the light, and is the angle between the surface normal at on the light and the direction from to (Figure 4.9).